Respuesta :

[tex]\begin{gathered} v_x=145\text{ m/s} \\ y=522\text{ m} \\ g=9.81m/s^2 \\ t=\text{?} \\ x=\text{?} \\ \text{For t} \\ y=\frac{gt^2}{2} \\ \text{Solving t} \\ 2y=gt^2 \\ t^2=\frac{2y}{g} \\ t=\sqrt{\frac{2y}{g}} \\ t=\sqrt{\frac{2(522m)}{9.81m/s^2}} \\ t=10\text{ s} \\ \text{The time in air is 10.3 s} \\ For\text{ x} \\ x=v_xt \\ x=(145\text{ m/s})(\text{10 s}) \\ x=1450\text{ m} \\ The\text{ object falls at 1450m from it was launched} \end{gathered}[/tex]

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