alishalizan
alishalizan alishalizan
  • 03-05-2020
  • Physics
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Help me with this question

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MathPhys
MathPhys MathPhys
  • 04-05-2020

Explanation:

Escape velocity is the point at which the kinetic energy is equal to the gravitational potential energy.

KE = PE

½ mv² = mgh

½ mv² = m (GM/r²) (r)

½ mv² = GMm/r

½ v² = GM/r

v = √(2GM/r)

The escape velocity is independent of the mass of the spacecraft.  So the escape velocity will be the same for both X and Y.

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